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Wednesday, December 03, 2014

Application of matrix congruence and similarity

A homework problem in statistical parameter estimation asks us to show that for two symmetric positive definite matrices Σ1 and Σ2.

If Σ1Σ2, then Σ11Σ12

Note that by assumption B=Σ2Σ1 is positive semi-definite.  If I can show that the resolvent identity of  Σ11Σ12, Σ12(Σ2Σ1)Σ11 is positive semi-definite, then the above statement is verified.

This requires the following two results:

Sylvester's Law of Inertia
Symmetric matrices A and B are congruent (i.e. there is a non-singular matrix C such that CTAC=B) if and only if A and B have the same inertia.  They have the same number of positive, negative and zero eigenvalues.
Theorem 1.
The product of a symmetric positive definite matrix A and a symmetric matrix B has the same inertia as B
Proof
Note that A1/2ABA1/2=A1/2BA1/2.  The right hand side is similar to AB, which means they have the same eigenvalues.  Since A1/2 is symmetric, the matrix A1/2BA1/2 is congruent to B.  By Sylvester's Law of inertia, the eignevalues of B have the same inertia as A1/2BA1/2 and also of AB.

The main point from Theorem 1 is that multiplying a positive definite matrix A to any symmetric matrix B will not change the inertia of the result.  Note that Σ12 and Σ11 are positive definite. We let Σ12=A1, Σ11=A2 and Σ2Σ1=B, and applying Theorem 1 twice, leads to Σ12(Σ2Σ1)Σ11 positive semi-definite.  We have shown Σ11Σ12 is indeed positive semi-definite.

Caution!
For real positive definite matrices, not all of them are symmetric!  For example, given a symmetric positive definite matrix B and a anti-symmetric matrix C (CT=C), the sum of which (A=B+C) is positive definite.   Extra care must be taken.  All references of positive definiteness are within the context of symmetric matrices. 

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