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Wednesday, January 07, 2015

Russell's Paradox

Shortly after the turn of the 19th century, Bertrand Russell demonstrated a hole in mathematical logic of set theory at the time.  A set can be member of itself. For sets R and S

R={S|RS}

The set R contains all sets that do not have themselves as members.

However, is R a member of itself?

Clearly not, since by definition R is the set of all sets that do not have themselves as member.

But then, if R does not have itself as a member then it must be a member of the set R

At that point in time, it created a huge stir among the mathematical community since most of what they do are based upon the foundation of sets.

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